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0.009x^2-0.08x+0.14=0
a = 0.009; b = -0.08; c = +0.14;
Δ = b2-4ac
Δ = -0.082-4·0.009·0.14
Δ = 0.00136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.08)-\sqrt{0.00136}}{2*0.009}=\frac{0.08-\sqrt{0.00136}}{0.018} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.08)+\sqrt{0.00136}}{2*0.009}=\frac{0.08+\sqrt{0.00136}}{0.018} $
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